11(x)=5(x^2+1)+16

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Solution for 11(x)=5(x^2+1)+16 equation: 



11(x)=5(x^2+1)+16

We move all terms to the left:

11(x)-(5(x^2+1)+16)=0



We calculate terms in parentheses: -(5(x^2+1)+16), so:

5(x^2+1)+16

We multiply parentheses

5x^2+5+16

We add all the numbers together, and all the variables

5x^2+21

Back to the equation:

-(5x^2+21)



We get rid of parentheses

-5x^2+11x-21=0

a = -5; b = 11; c = -21;
Δ = b2-4ac
Δ = 112-4·(-5)·(-21)
Δ = -299
Delta is less than zero, so there is no solution for the equation

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